Algebra

Solving quadratic equations three ways

A quadratic equation is any equation that can be written as ax² + bx + c = 0, where a is not zero. It might look intimidating, but there are just three tools for solving it, and you can usually tell which to reach for within a few seconds.

Method 1: Factorising

Best when the numbers are friendly. You are looking for two brackets that multiply out to the original.

Solve x² + 7x + 12 = 0. Find two numbers that multiply to 12 and add to 7: that is 3 and 4. So (x + 3)(x + 4) = 0. For a product to be zero, one bracket must be zero, so x = -3 or x = -4.

Method 2: The quadratic formula

Works every time, even when the numbers are ugly. The formula is x = (-b ± √(b² - 4ac)) ÷ 2a.

Solve 2x² - 3x - 5 = 0. Here a = 2, b = -3, c = -5. The discriminant is 9 + 40 = 49, and √49 = 7. So x = (3 ± 7) ÷ 4, which gives x = 2.5 or x = -1.

Method 3: Completing the square

Useful when you are asked for the vertex or need to rewrite the equation. Solve x² + 6x + 2 = 0.

  1. Move the constant: x² + 6x = -2.
  2. Add half the x-coefficient squared (3² = 9) to both sides: x² + 6x + 9 = 7.
  3. Write the left as a square: (x + 3)² = 7.
  4. Take square roots: x + 3 = ±√7, so x = -3 ± √7, about -0.35 or -5.65.

Which method should I use?

SituationUse
Small whole numbers, and b and c suggest an obvious pairFactorising
Awkward numbers, decimals or a calculator allowedFormula
You need the turning point or a rewritten formCompleting the square
Not sureFormula, then check by substituting

What the discriminant tells you

Before going any further, calculate b² - 4ac. If it is positive, expect two real answers. If it is zero, there is one repeated answer. If it is negative, the parabola never touches the x-axis and there are no real solutions. Knowing this in advance stops you wasting time on a factorisation that cannot work.

Always check

Put each answer back into the original equation. With x = 2.5 in 2x² - 3x - 5: 12.5 - 7.5 - 5 = 0. Correct. You can also confirm with the quadratic equation solver, which shows the discriminant, both roots and the vertex.

Try it yourself

Check each of your answers with the quadratic solver.

Quadratic Equation Solver

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